TCP retransmissions (reliable data transmission with ACK loss)
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 117 and every segment sent to the receiver each contains 298 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 2 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.
Question List
1. What is the sequence number of the segment sent at t=1?
2. What is the sequence number of the segment sent at t=2?
3. What is the sequence number of the segment sent at t=3?
4. What is the sequence number of the segment sent at t=4?
5. What is the sequence number of the segment sent at t=5?
6. What is the value of the ACK sent at t=8? (If segment lost, write 'x')
7. What is the value of the ACK sent at t=9? (If segment lost, write 'x')
8. What is the value of the ACK sent at t=10? (If segment lost, write 'x')
9. What is the value of the ACK sent at t=11? (If segment lost, write 'x')
10. What is the value of the ACK sent at t=12? (If segment lost, write 'x')
11. What is the sequence number of the segment sent at t = 15? (If ACK never arrives, write 'x')
12. What is the sequence number of the segment sent at t = 16? (If ACK never arrives, write 'x')
13. What is the sequence number of the segment sent at t = 17? (If ACK never arrives, write 'x')
14. What is the sequence number of the segment sent at t = 18? (If ACK never arrives, write 'x')
15. What is the sequence number of the segment sent at t = 19? (If ACK never arrives, write 'x')
Solution
1. The sequence number of the first segment is the starting sequence number, which is 117.
2. The sequence number of the second segment is = 117 + 298 = 415.
3. The sequence number of the third segment is = 415 + 298 = 713.
4. The sequence number of the fourth segment is = 713 + 298 = 1011.
5. The sequence number of the fifth segment is = 1011 + 298 = 1309.
6. The ACK value is the sequence number of the next expected segment, which is 415.
7. The ACK value is the sequence number of the next expected segment, which is 713.
8. Since the segment was lost, the ACK is never sent, so the answer is x.
9. Since the segment was lost, the ACK is never sent, so the answer is x.
10. The ACK value is the sequence number of the next expected segment, which is 713.
11. The sequence number of this segment is calculated the same way as the first five segments. The sequence number is 1607.
12. The sequence number of this segment is calculated the same way as the first five segments. The sequence number is 1905.
13. Since there was nothing to send (as we're waiting for ACKs), the answer is x.
14. Since there was nothing to send (as we're waiting for ACKs), the answer is x.
15. Since there was nothing to send (as we're waiting for ACKs), the answer is x.
That's incorrect
That's correct
The answer was: 117
The answer was: 415
The answer was: 713
The answer was: 1011
The answer was: 1309
The answer was: 415
The answer was: 713
The answer was: x
The answer was: x
The answer was: 713
The answer was: 1607
The answer was: 1905
The answer was: x
The answer was: x
The answer was: x