TCP retransmissions (reliable data transmission with ACK loss)
Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 147 and every segment sent to the receiver each contains 301 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but one of the ACKs is lost. Assume there are no timeouts and any out of order segments received are thrown out.
Question List
1. What is the sequence number of the segment sent at t=1?
2. What is the sequence number of the segment sent at t=2?
3. What is the sequence number of the segment sent at t=3?
4. What is the sequence number of the segment sent at t=4?
5. What is the sequence number of the segment sent at t=5?
6. What is the value of the ACK sent at t=8? (If segment lost, write 'x')
7. What is the value of the ACK sent at t=9? (If segment lost, write 'x')
8. What is the value of the ACK sent at t=10? (If segment lost, write 'x')
9. What is the value of the ACK sent at t=11? (If segment lost, write 'x')
10. What is the value of the ACK sent at t=12? (If segment lost, write 'x')
11. What is the sequence number of the segment sent at t = 15? (If ACK never arrives, write 'x')
12. What is the sequence number of the segment sent at t = 16? (If ACK never arrives, write 'x')
13. What is the sequence number of the segment sent at t = 17? (If ACK never arrives, write 'x')
14. What is the sequence number of the segment sent at t = 18? (If ACK never arrives, write 'x')
15. What is the sequence number of the segment sent at t = 19? (If ACK never arrives, write 'x')
Solution
1. The sequence number of the first segment is the starting sequence number, which is 147.
2. The sequence number of the second segment is = 147 + 301 = 448.
3. The sequence number of the third segment is = 448 + 301 = 749.
4. The sequence number of the fourth segment is = 749 + 301 = 1050.
5. The sequence number of the fifth segment is = 1050 + 301 = 1351.
6. The ACK value is the sequence number of the next expected segment, which is 448.
7. The ACK value is the sequence number of the next expected segment, which is 749.
8. The ACK value is the sequence number of the next expected segment, which is 1050.
9. Since the segment was lost, the ACK is never sent, so the answer is x.
10. The ACK value is the sequence number of the next expected segment, which is 1050.
11. The sequence number of this segment is calculated the same way as the first five segments. The sequence number is 1652.
12. Since there was nothing to send (as we're waiting for ACKs), the answer is x.
13. The sequence number of this segment is calculated the same way as the first five segments. The sequence number is 1953.
14. The sequence number of this segment is calculated the same way as the first five segments. The sequence number is 2254.
15. Since there was nothing to send (as we're waiting for ACKs), the answer is x.
That's incorrect
That's correct
The answer was: 147
The answer was: 448
The answer was: 749
The answer was: 1050
The answer was: 1351
The answer was: 448
The answer was: 749
The answer was: 1050
The answer was: x
The answer was: 1050
The answer was: 1652
The answer was: x
The answer was: 1953
The answer was: 2254
The answer was: x