### CDMA - Advanced

This time, assume there are 3 senders whom interfere with eachother and
that the interfering transmitted bit signals are additive. The value received at a
receiver, however, is now the sum of the transmitted bits from all senders.

Assume that sender 1 has a CDMA code of (1, -1, 1, 1, -1, -1, 1), sender 2 has a CDMA code of (1, 1, -1, 1, -1, 1, -1), and sender 3 has a CDMA code of (1, 1, -1, -1, -1, -1, 1) and their combined output is: (-1, 1, -1, 1, 1, 3, -3)

### Question List

1. Assuming you are receiver 1, what is the decoded bit? If it can't be done, answer with 'n/a'

2. Assuming you are receiver 2, what is the decoded bit? If it can't be done, answer with 'n/a'

3. Assuming you are receiver 3, what is the decoded bit? If it can't be done, answer with 'n/a'

### Solution

1. Because the CDMA codes weren't well chosen, interference will render the receiver unable to decode the original bit

2. The decoded bit is: 1 for sender 2

3. The decoded bit is: -1 for sender 3

That's incorrect

That's correct

The answer was: n/a

The answer was: 1

The answer was: -1